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Newsgroups: sci.math
From: Jack Schmidt <Jack.Schmidt.SciM...@gmail.com>
Date: Thu, 24 Jul 2008 09:41:03 EDT
Local: Thurs, Jul 24 2008 9:41 pm
Subject: Re: - - products of subgroups
crossedproduct replied at http://mathforum.org/kb/thread.jspa?messageID=6305531
>>crossedproduct asked at http://mathforum.org/kb/thread.jspa?messageID=6305486 There are still counterexamples with G of order 8. >>> Suppose P and Q subgroups of a group G such that P >>> and QP are normal in G. >>> If g is any element of G, denote by x^g the conjugate >>> If p is in P and q is in Q, then for any g in G, >>> My question is: why does it follow that q^g must lie If this is too large to imagine, then you may be interested in the counterexample with G of order 6. Please try to work out examples. I have posted to you numerous counterexamples which you do not appear to read. You must Sign in before you can post messages.
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