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Newsgroups: sci.math
From: Jack Schmidt <Jack.Schmidt.SciM...@gmail.com>
Date: Wed, 23 Jul 2008 18:27:29 EDT
Local: Thurs, Jul 24 2008 6:27 am
Subject: Re: - - products of subgroups
crossedproduct asked at http://mathforum.org/kb/thread.jspa?messageID=6305486
> Suppose P and Q subgroups of a group G such that P There are counterexamples with G of order 8. > and QP are normal in G. > If g is any element of G, denote by x^g the conjugate > If p is in P and q is in Q, then for any g in G, > (qp)^g = (q^g)(p^g) is in QP, > since QP is normal. But p^g is in P, since P is > My question is: why does it follow that q^g must lie You must Sign in before you can post messages.
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